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Work, Energy and Power is a scoring chapter, and that is exactly why it is dangerous. The formulas are short, so students stop checking the angle, the sign and the units. Ten questions below, with the answer key and a hint for each.
What this chapter carries in NEET(UG)
- Usually 2 to 3 questions every year, which is 8 to 12 marks.
- Most of them come from the work-energy theorem, spring energy, collisions and power.
- The commonest loss here is forgetting the cos θ in the work formula.
What the syllabus says
In the syllabus (Unit 4, Work, Energy and Power): Work done by a constant force and by a variable force, kinetic and potential energy, the work–energy theorem, power, potential energy of a spring, conservation of mechanical energy, conservative and non-conservative forces, motion in a vertical circle, elastic and inelastic collisions in one and two dimensions.
Taken from the NMC syllabus for NEET (UG) 2026, the latest one published. See the full syllabus, unit by unit.
Formulas you must know by heart
| Work done by a constant force | W = Fd cos θ |
| Kinetic energy | KE = ½mv2 |
| Potential energy near the earth | PE = mgh |
| Work-energy theorem | Wnet = ΔKE |
| Energy stored in a spring | U = ½kx2 |
| Power | P = W/t = Fv |
| Speed after a free fall through h | v = √(2gh) |
| Elastic collision | both momentum and kinetic energy are conserved |
| Inelastic collision | momentum is conserved, kinetic energy is not |
Remember the third one. In uniform circular motion the force is always perpendicular to the motion, so it does no work at all.
Ten questions. Give yourself ten minutes.
Write your answers down before you scroll. A question you looked up is a question you have not answered.
Q1. A force of 10 N moves a body through 5 m, acting at 60° to the direction of motion. The work done is
- (a) 0 J
- (b) 25 J
- (c) 43.3 J
- (d) 50 J
Q2. The kinetic energy of a body of mass 2 kg moving at 4 m/s is
- (a) 4 J
- (b) 8 J
- (c) 16 J
- (d) 32 J
Q3. A stone is whirled in a horizontal circle at constant speed. The work done by the centripetal force in one full circle is
- (a) zero
- (b) positive
- (c) negative
- (d) depends on the radius
Q4. A body of mass 5 kg is lifted through 10 m. Taking g = 10 m/s², the gain in potential energy is
- (a) 50 J
- (b) 250 J
- (c) 500 J
- (d) 1000 J
Q5. A machine does 100 J of work in 5 s. Its power is
- (a) 5 W
- (b) 20 W
- (c) 50 W
- (d) 500 W
Q6. A spring of force constant 200 N/m is compressed by 0.1 m. The energy stored in it is
- (a) 0.5 J
- (b) 1 J
- (c) 2 J
- (d) 20 J
Q7. In a perfectly elastic collision between two bodies, the quantity or quantities conserved are
- (a) momentum only
- (b) kinetic energy only
- (c) both momentum and kinetic energy
- (d) neither of the two
Q8. A body falls freely from a height h. Its speed on reaching the ground is
- (a) gh
- (b) √(gh)
- (c) 2gh
- (d) √(2gh)
Q9. The work-energy theorem states that the net work done on a body equals its change in
- (a) momentum
- (b) potential energy
- (c) kinetic energy
- (d) power
Q10. A person of mass 60 kg climbs a height of 2 m in 4 s. Taking g = 10 m/s², the power developed is
- (a) 120 W
- (b) 240 W
- (c) 300 W
- (d) 1200 W
Answer key, with a hint for each
| Q1 | (b) | W = Fd cos θ = 10 × 5 × cos 60° = 10 × 5 × 0.5 = 25 J. |
| Q2 | (c) | KE = ½ × 2 × 16 = 16 J. |
| Q3 | (a) | The force points to the centre, the motion is along the circle. The angle is 90°, so cos θ = 0. |
| Q4 | (c) | PE = mgh = 5 × 10 × 10 = 500 J. |
| Q5 | (b) | P = W/t = 100/5 = 20 W. |
| Q6 | (b) | U = ½kx2 = ½ × 200 × 0.01 = 1 J. Square the 0.1 first. |
| Q7 | (c) | Elastic means kinetic energy survives as well. Momentum is conserved in every collision. |
| Q8 | (d) | v = √(2gh), straight from ½mv2 = mgh. |
| Q9 | (c) | Net work changes the kinetic energy. That is the whole theorem. |
| Q10 | (c) | P = mgh/t = (60 × 10 × 2)/4 = 300 W. |
Now mark yourself honestly
NEET(UG) marks the way it marks. Use the same rule here:
- +4 for a right answer
- −1 for a wrong one
- 0 for a blank
So ten questions here are out of 40. In the real paper, 45 Physics questions are out of 180.
If you scored 32 or more, the basics of this chapter are secure. Move to harder questions, not more of these.
If you scored below 24, do not feel bad about it. You have just found out something useful before the exam did. Go back to the formula table above, learn it properly, and sit these ten again tomorrow.
And if you guessed a few and they landed, count those as wrong. A guess that works once will not work in May.
The full chapter, on a clock
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