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Current Electricity gives away marks more easily than almost any other chapter in NEET(UG) Physics, and it takes them back just as fast when a student mixes up series and parallel under pressure. Ten questions below, with the answer key and a hint for each.
What this chapter carries in NEET(UG)
- Usually 3 to 4 questions every year, which is 12 to 16 marks.
- Most of them come from resistance combinations, Ohm’s law, cells with internal resistance and power.
- Numbers here are small and clean. That is exactly why losing marks in this chapter hurts.
What the syllabus says
In the syllabus (Unit 12, Current Electricity): Electric current, drift velocity and mobility and how they relate to current, Ohm’s law, electrical resistance, I–V characteristics of ohmic and non-ohmic conductors, electrical energy and power, resistivity and conductivity, resistors in series and parallel, temperature dependence of resistance, internal resistance, potential difference and emf of a cell, cells in series and parallel, Kirchhoff’s laws and their applications, the Wheatstone bridge and the metre bridge.
Taken out in 2024: the potentiometer, its principle and its applications; the colour code for carbon resistors; resistances of different materials.
Taken from the NMC syllabus for NEET (UG) 2026, the latest one published. See the full syllabus, unit by unit.
Formulas you must know by heart
| Ohm’s law | V = IR |
| Resistance of a wire | R = ρL/A |
| Series | R = R1 + R2 + … |
| Parallel | 1/R = 1/R1 + 1/R2 + … |
| Current and drift velocity | I = neAvd |
| Cell with internal resistance | I = ε / (R + r) |
| Power | P = VI = I2R = V2/R |
| Wheatstone bridge, balanced | P/Q = R/S |
| Metal conductor | resistance rises as temperature rises |
The last two are the ones students forget in the exam hall. Write them on the first page of your notebook.
Ten questions. Give yourself ten minutes.
Write your answers down before you scroll. A question you looked up is a question you have not answered.
Q1. A wire has resistance R. If its length is doubled and its area of cross-section is halved, the new resistance is
- (a) R/4
- (b) R
- (c) 2R
- (d) 4R
Q2. Two resistors of 6 Ω and 3 Ω are joined in parallel. Their combined resistance is
- (a) 1 Ω
- (b) 2 Ω
- (c) 4.5 Ω
- (d) 9 Ω
Q3. A cell of emf 12 V and internal resistance 1 Ω is connected across a 5 Ω resistor. The current in the circuit is
- (a) 1 A
- (b) 2 A
- (c) 2.4 A
- (d) 12 A
Q4. A current of 2 A flows through a 5 Ω resistor. The power dissipated is
- (a) 2.5 W
- (b) 10 W
- (c) 20 W
- (d) 50 W
Q5. The resistance of a 100 W, 220 V bulb when it is working normally is
- (a) 2.2 Ω
- (b) 48.4 Ω
- (c) 220 Ω
- (d) 484 Ω
Q6. Kirchhoff’s junction rule is a statement of the conservation of
- (a) energy
- (b) charge
- (c) momentum
- (d) mass
Q7. The drift velocity of free electrons in a conductor is related to the current by
- (a) I = neAvd
- (b) I = neA/vd
- (c) I = nevd/A
- (d) I = nAvd/e
Q8. Three identical resistors, each of resistance R, are joined in series. The combined resistance is
- (a) R/3
- (b) R
- (c) 2R
- (d) 3R
Q9. When the temperature of a metallic conductor is raised, its resistance
- (a) decreases
- (b) increases
- (c) stays the same
- (d) first falls, then rises
Q10. A charge of 60 C passes through a wire in 2 minutes. The current in the wire is
- (a) 0.5 A
- (b) 1 A
- (c) 2 A
- (d) 30 A
Answer key, with a hint for each
| Q1 | (d) | R = ρL/A. Length ×2 and area ÷2 together give 4R. |
| Q2 | (b) | 6 × 3 / (6 + 3) = 18/9 = 2 Ω. In parallel the answer is always smaller than the smallest resistor. |
| Q3 | (b) | I = ε/(R + r) = 12/(5 + 1) = 2 A. The internal resistance is in series, do not drop it. |
| Q4 | (c) | P = I2R = 4 × 5 = 20 W. |
| Q5 | (d) | R = V2/P = 220 × 220 / 100 = 484 Ω. |
| Q6 | (b) | Whatever charge flows in must flow out. That is conservation of charge. |
| Q7 | (a) | I = neAvd. More carriers, bigger area or faster drift all mean more current. |
| Q8 | (d) | In series resistances simply add: R + R + R = 3R. |
| Q9 | (b) | In a metal, more collisions at higher temperature, so more resistance. Semiconductors behave the opposite way. |
| Q10 | (a) | I = q/t = 60/120 = 0.5 A. Two minutes is 120 seconds, not 2. |
Now mark yourself honestly
NEET(UG) marks the way it marks. Use the same rule here:
- +4 for a right answer
- −1 for a wrong one
- 0 for a blank
So ten questions here are out of 40. In the real paper, 45 Physics questions are out of 180.
If you scored 32 or more, the basics of this chapter are secure. Move to harder questions, not more of these.
If you scored below 24, do not feel bad about it. You have just found out something useful before the exam did. Go back to the formula table above, learn it properly, and sit these ten again tomorrow.
And if you guessed a few and they landed, count those as wrong. A guess that works once will not work in May.
The full chapter, on a clock
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